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50(1-x^2)-75x=0
We multiply parentheses
-50x^2-75x+50=0
a = -50; b = -75; c = +50;
Δ = b2-4ac
Δ = -752-4·(-50)·50
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15625}=125$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-125}{2*-50}=\frac{-50}{-100} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+125}{2*-50}=\frac{200}{-100} =-2 $
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